Three grams of salt of molecular weight 30 is dissolved in `250 g` of water. The molality of the solution is….
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The correct Answer is:
`(0.4)`
`"Molarity" = ("Number of moles of solute")/("Volume of solution in litre")` `= ("Weight of solute")/("Molar mass") xx (1000)/("Volume in mL") = (3)/(30) xx (1000)/(250) = 0.4 M`
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