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The total number of electrons present in...

The total number of electrons present in `18 mL` of water is ……

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The correct Answer is:
`(6.023 xx 10^(24))`
Considering density of water to be `1.0g//mL, 18 mL` of water is `18 g (1.0 mol)` of water and it contain Avogadro number of molecules. Also one molecule of water contain
`2 xx ("one from each H-atom") + 8 xx ("from oxygen atom")`
`= 10 "electrons"`.
`rArr 1.0` mole of `H_(2)O` contain `= 10 xx 6.023 xx 10^(23)`
`= 6.023 xx 10^(24)` electrons.
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