A compound `H_(2)X` with molar mass of `80 g` is dissolved in a solvent having density of `0.4 g mL^(-1)`. Assuming no change in volume upon dissolution, the molality of a `3.2` molar solution is
Text Solution
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The correct Answer is:
-8
PLAN This problem can be solved by using concept of conversion of molarity into molality. Molarity `= 3.2 M` Let volume of solution `= 1000 mL = "Volume of solvent"` Mass of solvent `= 1000 xx 0.4 = 400 g` Since, molarity of solution is `3.2` molar `:. n_("solute") = 3.2 mol` Molarity (m) `= (3.2)/(400//1000) = 8` Hence, correct integer is (8).
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