Home
Class 12
CHEMISTRY
A compound H(2)X with molar mass of 80 g...

A compound `H_(2)X` with molar mass of `80 g` is dissolved in a solvent having density of `0.4 g mL^(-1)`. Assuming no change in volume upon dissolution, the molality of a `3.2` molar solution is

Text Solution

Verified by Experts

The correct Answer is:
-8

PLAN This problem can be solved by using concept of conversion of molarity into molality.
Molarity `= 3.2 M`
Let volume of solution `= 1000 mL = "Volume of solvent"`
Mass of solvent `= 1000 xx 0.4 = 400 g`
Since, molarity of solution is `3.2` molar
`:. n_("solute") = 3.2 mol`
Molarity (m) `= (3.2)/(400//1000) = 8`
Hence, correct integer is (8).
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Subjective Questions|2 Videos
  • SOLUTIONS AND COLLIGATIVE PROPERTIES

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Assertion-Reason Type|2 Videos
  • STATES OF MATTER

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise INTEGER_TYPE|2 Videos

Similar Questions

Explore conceptually related problems

A compound H_(2)X with molar weigth of 80g is dissolved in a solvent having density of 0.4 g mol^(-1) . Assuming no change in volume upon dissolution, the molarity of a 3.2 molar solution is

A compound H_(2)X with molar mass of 80 g is dissolved in a solvent having density of 0.4 g mL^(-1) . Assuming no change in volume upon dissolution, what is the molality of 3.2 M solution of the compound ?

A compound MX_(2) with molar mass of 80 g is dissolved in a solvent having density 0.4 g mL^(-1) . Assuming that there is no change in volume upon dissociation, what is the molality of a 3.2 molar solution ?

4.5g mass of a substance (molar mass = 90g/mol) is dissolved in 250ml solution, the molarity of solution is

The molarity of 5 molal aqueous solution of NaOH having density 1.2g/cc is :

The molality of 49% by volume of H_(2)SO_(4) solution having density 1.49 g/mL is……