A plant virus is found to consist of uniform cylindrical particle of `150 Å` in diameter 5000 Å long. The specific volume of the virus is 0.75 `mLg^(-1)`. If the virus is considered to be a single particle, find its molar mass.
Text Solution
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The correct Answer is:
`(4.3 xx 10^(-3))`
Volume of one cyclinderical plant virus `= pir^(2) l` `= 3.14 (75 xx 10^(-8))^(2) xx 5000 xx 10^(-8) cm^(3) = 8.83 xx 10^(-17) cm^(3)` `rArr` Mass of one virus `= ("Volume of a virus")/("Specific volume")` `= (8.83 xx 10^(-17) cm^(3))/(0.75 cm^(3) g^(-1)) = 1.1773 xx 10^(-160 g` `rArr` Molar mass of virus = Mass of one virus `xx` Avogadro's number `= 1.1773 xx 10^(-16)xx 6.023 xx 10^(23) g` `= 70.91 xx 10^(6) g`
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