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The density of 3 M sodium of thiosulphat...

The density of `3 M` sodium of thiosulphate solution `(Na_(2)S_(2)O_(3))` is `1.25 g mL^(-1)`. Calculate
a. The precentage by weight of sodium thiosulphate.
b. The mole fraction of sodium thiosulphate.
c. The molalities of `Na^(o+)` and `S_(2)O_(3)^(2-)` ions.

Text Solution

Verified by Experts

The correct Answer is:
(i) `37.92`, (ii) `0.065`, (iii) `7.73m`
Let us consider `1.0 L` solution for all the calculation.
(i) Weight of `1 L` solution `=1250 g`
Weight of `Na_(2)S_(2)O_(3)=3xx158=474 g`
`implies` Weight percentage of `Na_(2)S_(2)O_(3)=(474)/(1250)xx100=37.92`
(ii) Weight of `H_(2)O` in `1 L` solution `=1250-474=776 g`
Mole fraction of `Na_(2)S_(2)O_(3)=(3)/(3+776/18)=0.065`
(iii) Molarity of `Na^(+)=(3xx2)/776 xx100=7.73m`
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