Home
Class 12
CHEMISTRY
Five millilitires of a gas (A) containin...

Five millilitires of a gas (A) containing only C and H was mixed with an excess of oxygen (30 ml) and the mixture was exploded by means of an electric spaek. After the explosion, the remaining volume of the mixed gasses was 25 ml. On adding a concentrated solution of KOH, the volume further diminished to 15 ml. The residual gas being pure oxyges.

The molecular formula of gas (A) is:

Text Solution

Verified by Experts

In the present case, `V prop n` ( `:'` all the volumes are measured under identical conditions of temperature and pressure) Hence, the reaction stoichiometry can be solving using volumes as :
`C_(x)H_(y) (g)+(x+y/4)O_(2) (g) rarr xCO_(2)(g)+y/2 H_(2)O (l)`
volume of `CO_(2)(g)+O_(2)(g)` (remaining unreacted)`=25`
`implies` volume of `CO_(2)(g)` produced
`=10` mL (`15` mL `O_(2)` remaining)
`:'" "1 mL C_(x)H_(y)` produces `x` mL of `CO_(2)`
`:." "5` mL `C_(x)H_(y)` will produces `5 xmL` of `CO_(2)=10` mL
`implies" "x=2`
Also, `1` mL `C_(x)H_(y)` combines with `(x+y/4)`mL of `O_(2)`
`5`mL `C_(x)H_(y)` will combine with `5(x+y/4)` mL of `O_(2)`
`implies 5(x+y/4)=15 (15" mL of "O_(2)" out of "30 mL)" "` (remaining unreacted)
`implies y=4`, hence hydrocarbon is `C_(2)H_(4)`.
Promotional Banner

Topper's Solved these Questions

  • SOME BASIC CONCEPTS OF CHEMISTRY

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Subjective Questions|2 Videos

  • SOLUTIONS AND COLLIGATIVE PROPERTIES

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Assertion-Reason Type|2 Videos

  • STATES OF MATTER

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise INTEGER_TYPE|2 Videos

Similar Questions

Explore conceptually related problems

Five millilitires of a gas (A) containing only C and H was mixed with an excess of oxygen (30 ml) and the mixture was exploded by means of an electric spaek. After the explosion, the remaining volume of the mixed gasses was 25 ml. On adding a concentrated solution of KOH, the volume further diminished to 15 ml. The residual gas being pure oxyges. Compound (C) is:

Five millilitires of a gas (A) containing only C and H was mixed with an excess of oxygen (30 ml) and the mixture was exploded by means of an electric spaek. After the explosion, the remaining volume of the mixed gasses was 25 ml. On adding a concentrated solution of KOH, the volume further diminished to 15 ml. The residual gas being pure oxyges. Compopund (F) is:

Five millilitires of a gas (A) containing only C and H was mixed with an excess of oxygen (30 ml) and the mixture was exploded by means of an electric spaek. After the explosion, the remaining volume of the mixed gasses was 25 ml. On adding a concentrated solution of KOH, the volume further diminished to 15 ml. The residual gas being pure oxyges. Compound (D) is:

Five millilitires of a gas (A) containing only C and H was mixed with an excess of oxygen (30 ml) and the mixture was exploded by means of an electric spaek. After the explosion, the remaining volume of the mixed gasses was 25 ml. On adding a concentrated solution of KOH, the volume further diminished to 15 ml. The residual gas being pure oxyges. Compound (B) is:

Five millilitires of a gas (A) containing only C and H was mixed with an excess of oxygen (30 ml) and the mixture was exploded by means of an electric spaek. After the explosion, the remaining volume of the mixed gasses was 25 ml. On adding a concentrated solution of KOH, the volume further diminished to 15 ml. The residual gas being pure oxyges. Compound (E) is:

5 " mL of " a gas A containing only C and H was mixed with an excess of O_2 (30 mL) and the mixture was exploded by means of electric sperk. After explosion, the remaining volume of the mixed gases was 25 mL. On adding a concentrated solution of KOH, the volume further diminished to 15 mL. The residual gas was pure oxygen, The molecular formula of the gas A is.

5 ml of a gas containing only carbon and hydrogen were mixed with an excess of oxygen (30 ml) and the mixture exploded by means of an electric spark. After the explosion, the volume of the mixed gases remaining was 25 ml. On adding a concentrated solution of potassium hydroxide, the volume further diminished to 15 ml of the residual gas being pure oxygen. All volumes have been reduced to N.T.P. Calculate the molecular formula of the hydrocarbon gas.

20ml CO was mixed with 50 ml of oxygen and the mixture was exploded. On cooling, the resulting mixture was shaken with KOH. Find the final gaseous volume