The vapour density of a mixture consisting of `NO_(2)` and `N_(2)O_(4)` is `38.3` at `275 K`. The number of moles of `NO_(2)` in the mixture:
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The correct Answer is:
`(0.437)`
From the vapour density information Molar mass = Vapour density`xx 2" " ( :' " Molar mass of "H_(2)=2)` `=38.3xx2=76.6` Now, let us consider `1.0` mole of mixture and it contains x mole of `NO_(2)` `implies 46x +92 (1-x)=76.6` `implies x=0.3348` Also, in `100 g` mixture, number of moles `=100/76.6` `implies` Moles of `NO_(2)` in mixture `=100/76.6xx0.3348=0.437`
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