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In the neutralization of Na(2)S(2)O(3) u...

In the neutralization of `Na_(2)S_(2)O_(3)` using `K_(2)Cr_(2)O_(7)` by idometry, the equivalent weight of `K_(2)Cr_(2)O_(7)` is

A

(molecular weight)/2

B

(molecular weight)/6

C

(molecular weight)/3

D

same as molecular weight

Text Solution

Verified by Experts

The correct Answer is:
B
The following reaction occur between `S_(2)O_(3)^(2-)` and `Cr_(2)O_(7)^(2-)`
`26H^(+) + 3S_(2)O_(3)^(2-) + 4Cr_(2)O_(7)^(2-) rarr 6SO_(4)^(2-) + 8Cr^(3+) +13 H_(2)O`
Change in oxidation number of `Cr_(2)O_(7)^(2-)` per formula unit is 6 (it is always fixed for `Cr_(2)O_(7)^(2-)`).
Hence, equivalent weight of `K_(2)Cr_(2)O_(7) = ("Molecular weight")/(6)`
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