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An aqueous solution of 6.3 g oxalic acid...

An aqueous solution of `6.3 g` oxalic acid dihydrate is made up to `250 mL`. The volume of `0.1 N NaOH` required to completely neutralise `10 mL` of this solution is

A

`40 mL`

B

`20 mL`

C

`10 mL`

D

`4 mL`

Text Solution

Verified by Experts

The correct Answer is:
A
Oxalic acid dihydrate `H_(2)C_(2)O_(4).2H_(2)O " mw = 126`
It is a dibasic acid, hence equivalent weight `= 63`
`rArr` Normality `= (6.3)/(63) xx (1000)/(250) = 0.4 N`
`rArr N_(1)V_(1) = N_(2)V_(2)`
`rArr 0.1 xx V_(1) = 0.4 xx 10`
Hence, `V_(1) = 40 mL`
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