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Oxidation number of P in Ba(H(2)PO(2))(2...

Oxidation number of `P` in `Ba(H_(2)PO_(2))_(2)` is

A

`+3`

B

`+2`

C

`+1`

D

`-1`

Text Solution

Verified by Experts

The correct Answer is:
C
In `Ba(H_(2)PO_(2))_(2)`, oxidation number of `Ba` is `+2`. Therefore,
`H_(2)PO_(2)^(2-) : 2 xx (-1) + x +2 xx (-2) = -1`
`rArr " " x = +1`
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