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For the reaction: I^(Theta)+ClO(3)^(Thet...

For the reaction: `I^(Theta)+ClO_(3)^(Theta)+H_(2)SO_(4)rarrCl^(Theta)+HSO_(4)^(Theta)+I_(2)`
The correct statement(s) in the balanced equation is/are

A

stoichiometric coefficient of `HSO_(4)^(-)` is 6

B

iodide is oxidised

C

sulphur is reduced

D

`H_(2)O` is one of the products

Text Solution

Verified by Experts

The correct Answer is:
A, B, D

PLAN This problem includes concept of redox reaction.A redox reaction consists of oxidation half-cell reaction and reduction half-cell reaction, Write both half-cell reactions, i.e., oxidation half-cell reaction and reduction half-cell reaction. Then balance both the equations.
Now determine the correct value of stoichiometry of `H_(2)SO_(4)`.
Oxidation half-reaction, `2I^(-) rarr I_(2) + 2e^(-)` ....(i)
Here, `I^(-)` is converted into `I_(2)`. Oxidation number of `I` is increasing from `-1` to 0 hence, this is a type of oxidation reaction.
Reduction half-reaction
`6H^(+) + ClO_(30^(-) + 6e^(-) rarr Cl^(-) + 3H_(2)O`
Here, `H_(2)O` releases as a product. Hence, option (d) is correct.
Multiplying equation (i) by 3 and adding in equation (ii)
`6I^(-) + ClO_(3)^(-) + 6H^(+) rArr Cl^(-) + 3I_(2)+3H_(2)O`
`6I^(-) + ClO_(3)^(-) + 6H_(2)SO_(4) rarr Cl^(-) + 3I_(2)+3H_(2)O+6HSO_(4)^(-)`
Stoichiometric coefficient of `HSO_(4)^(-)` is 6.
Hence, option (a), (b) and (d) are correct.
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