Calculate the amount of calcium oxide required when it reacts with `852 g` of `P_(4) O_(10)`.
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The correct Answer is:
`(1008 g)`
The balanced reaction is `6CaO +P_(4)O_(10) rarr 2Ca_(3)(PO_(4))_(2)` Moles of `P_(4)O_(10) = (852)/(284) = 3` Moles of `CaO` required `= 3xx6 = 18` Mass of `CaO` required `= 18 xx 56 = 1008 g`
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