Calculate the volume of 0.5 M `H_2SO_4` required to dissolve 0.5 g of copper (II) carbonate `(CuCO_3)`.

Answer

`(8.096 mL)`

Explanation

The balanced chemical reaction is
`CuCO_(3) + H_(2)SO_(4) rarr CuSO_(4)+H_(2)O + CO_(2)`
millimol of `CuCO_(3) = (0.5 xx 1000)/(123.5) = 4.048`
`rArr` Millimol of `H_(2)SO_(4)` required `= 4.048`
`because` Millimol =Molarity `xx` Volume (in mL)
`rArr` Volume `= (4.048)/(0.50) = 8.096 mL`