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To a 25 mL H(2)O(2) solution excess of a...

To a 25 mL `H_(2)O_(2)` solution excess of an acidified solution of potassium iodide was added. The iodine liberated required 20 " mL of " 0.3 N sodium thiosulphate solution Calculate the volume strength of `H_(2)O_(2)` solution.

Text Solution

Verified by Experts

The correct Answer is:
`(1.334 V)`
Meq of `H_(2)O = "Meq of" I_(2) = "Meq of" Na_(2)S_(2)O_(3)`
If `N` is normality of `H_(2)O`, then
`N xx 25 = 0.3 xx 20`
`rArr N = 0.24`
`rArr` Volume strength `= N xx 5.6 =1.334 V`
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