Home
Class 12
CHEMISTRY
The kinetic energy of an electron in the...

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is [`a_0` is Bohr radius] :

A

`(h^(2))/(4pi^(2)ma_(0)^(2))`

B

`(h^(2))/(16 pi^(2) ma_(0)^(2))`

C

`(h^(2))/(32 pi^(2)ma_(0)^(2))`

D

`(h^(2))/(64pi^(2)ma_(0)^(2))`

Text Solution

Verified by Experts

The correct Answer is:
C
Promotional Banner

Topper's Solved these Questions

  • ATOMIC STRUCTURE

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Topic 2|1 Videos

  • ATOMIC STRUCTURE

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Match the Columns|4 Videos

  • ARYL HALIDE AND PHENOLS

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise JEE Main And Advanced|50 Videos

  • BENZENE AND ALKYL BENZENE

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise JEE Main And Advanced|56 Videos

Similar Questions

Explore conceptually related problems

The kinetic energy of the electron in the second Bohr's orbit of a hydrogen atom [ a_(0) is Bohr's radius] is

The energy of an electron in the nth Bohr orbit of hydrogen atom is

The kinetic energy of electron in the first Bohr orbit of the hydrogen atom is

The kinetic energy of an electron in the second Bohr orbit of a hydrogen atom is equal to (h^(2))/(x ma_(0)^(2)) . The value of 10x is __________. ( a_(0) is radius of Bohr's orbit) (Nearest integer) [Given : pi=3.14 ]

Radius of Bohr's orbit of hydrogen atom is

lonization energy of an electron present in the second Bohr's orbit of hydrogen is

The radius of second Bohr’s orbit of Hydrogen atom is: