Home
Class 12
CHEMISTRY
The Henry's law constant for the solubil...

The Henry's law constant for the solubility of `N_(2)` gas in water at `298K` is `1.0 xx 10^(5)` atm. The mole fraction of `N_(2)` in air is `0.8`. The number of moles of `N_(2)` from air dissolved in 10 moles of water at 298K and 5 atm pressure is

A

`4.0 xx 10^(-4)`

B

`4.0 xx 10^(-5)`

C

`5.0 xx 10^(-4)`

D

`4.0 xx 10^(-6)`

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS AND COLLIGATIVE PROPERTIES

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Objective Questions II|1 Videos

  • SOLUTIONS AND COLLIGATIVE PROPERTIES

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise TOPIC 2 (Objective Questions I)|1 Videos

  • SOLID STATE

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Passage|1 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Subjective Questions|2 Videos

Similar Questions

Explore conceptually related problems

The Henry's law constant for the solubility of N_(2) gas in water at 298 K is 1.0 xx 10^(5) atm . The mole fraction of N_(2) in air is 0.8 . The number of moles of N_(2) from air dissolved in 10 moles of water at 298 K and 5 atm . Pressure is:

The Henry's law constant fo the solubility of N_(2) gas in water at 298 K is 1.0xx10^(5) atm. The mole fraction of N_(2) in air is 0.8. The number of moles of N_(2) from air dissolved in 10 moles of water at 298K and 5 atm pressue is

Henry 's law constant for the solubility of N_(2) gas in water at 298 K is 1.0 xx 10^(5) atm . The mole fraction of N_(2) in air is 0.6 . The number of moles of N_(2) from air dissolved in 10 moles of water at 298 K and 5 atm pressure is a. 3.0 xx 10^(-4) b. 4.0 xx 10^(-5) c. 5.0 xx 10^(-4) d. 6.0 xx 10^(-6)

Henry's law constant for the solubility of nitrogen gas in water at 298 K is 1.0 xx 10^(-5) atm . The mole fraction of nitrogen in air is 0.8 .The number of moles of nitrogen from air dissolved in 10 mol of water at 298 K and 5 atm pressure is

The Henry's law constant for the solubility of N_(2) gas in water at 298 K is 1xx10^(-5)" atm" . The mole fraction of N_(2) in air in 0.8. If the number of moles of N_(2) of air dissolved in 10 moles of water at 298 K and 5 atm x. 10^(-4) . Find the value of x.

The Henry's law constant for the solubility of N_(2) gas i water at 298K is 1xx10^(5) atm. The mole fraction of N_(2) air is 0.8 . The number of mole of N_(2) of dissolved in 10 mole of water at 298K and 5 atm. are x xx10^(4) . Find the value of x .

Volume of 0.5 mole of a gas at 1 atm. Pressure and 273 K is