Home
Class 12
CHEMISTRY
The vapour pressure of pure benzene is 6...

The vapour pressure of pure benzene is `639.7 mm Hg` and the vapour pressure of solution of a solute in benzene at the temperature is `631.9 mm Hg`. Calculate the molality of the solution.

Text Solution

Verified by Experts

The correct Answer is:
`0.158`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS AND COLLIGATIVE PROPERTIES

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Objective Questions II|1 Videos
  • SOLUTIONS AND COLLIGATIVE PROPERTIES

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise TOPIC 2 (Objective Questions I)|1 Videos
  • SOLID STATE

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Passage|1 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    IIT-JEE PREVIOUS YEAR (CHEMISTRY)|Exercise Subjective Questions|2 Videos

Similar Questions

Explore conceptually related problems

The vapour pressure of pure benzene at 25^@C is 640.0 mm Hg and vapour pressure of a solution of a solute in benzene is 25^@C is 632.0 mm Hg. Find the freezing point of the solution if k_f for benzene is 5.12 K/m. (T_("benzene")^@ = 5.5^@C)

The vapour pressure of water is 17.54mm Hg at 293 K. Calculate vapour pressure of 0.5 molal solution of a solute in it.

The vapour pressure of pure benzene at 25^@C is 640 mm Hg and that of the solute A in benzene is 630 mm of Hg. The molality of solution of

The vapour pressure of a pure liquid A is 40 mm Hg at 310 K . The vapour pressure of this liquid in a solution with liquid B is 32 mm Hg . The mole fraction of A in the solution, if it obeys Raoult's law, is: