A solution is a mixture of `0.06M` KCl and `0.06 M Kl. AgNO_(3)` solution is being added drop by drop till AgCl starts precipitating `(K_(sp)AgCl=1xx10^(-10)` and `K_(sp)Agl=4xx10^(-16))`. The concentration of iodide ion at this instant will be nearly equal to `:`

Options

A. `4.0xx10^(-5)M`
B. `4xx10^(-8)M`
C. `2.4xx10^(-8)M`
D. `2.4xx10^(-7)M`

Answer

4

Explanation

When AgCl Starts precipitating `[Ag^(+)]=(10^(-10))/(0.06)`. At that time conc of `[I^(-)]=(4xx10^(-16))/(10^(-10))=2.4xx10^(-7)`