`A+3B harr 2C+D`
For this hypothetical reaction, initial moles of A is twice that of B. If at equilibrium, moles of B and C are equal, the percent of B reacted is `:`

Options

A. `10%`
B. `20%`
C. `40%`
D. `60%`

Answer

4

Explanation

`{:(,A,+,3B,leftrightarrow,2C,+,D,),("initial mole",2a,,a,,0,,0,),("after reaction",2a-x,,a-3x,,2x,,x,),("given that",a-3x=2x,,,,,,,),(,impliesx=a//5,,,,,,,):}`
`%` of B reacted `=3x//a xx 100=3//5xx100=60%`