In the reaction `4A+2B+3C rarr A_(4)B_(2)C_(3)` what will bw the number of moles of product formed. Starting from 2 moles of `A, 1.2` moles of `B & 1.44` moles of `C :`

Options

A. `0.5`
B. `0.6`
C. `0.48`
D. `4.64`

Answer

3

Explanation

`{:(,4A,+,2B,+,3C,rarr,A_(4)B_(2)C_(3)),("Initial mole",2,,1.2,,1.44,,0),("final mole",,,,,0,,0.48):}`
C is limiting reagent.
`:.` moles of `A_(4)B_(2)C_(3)` is `0.48`,