`2KI+I_(2)+22HNO_(3)rarr2HIO_(3)+2KIO_(3)+22NO_(2)+10H_(2)O`
If 3 mole of `KI & 2` moles `I_(2)` are reacted with excess of `HNO_(3)`. Volume of `NO_(2)` gas evolved at `NTP` is `:`
`2KI+I_(2)+22HNO_(3)rarr2HIO_(3)+2KIO_(3)+22NO_(2)+10H_(2)O`

Options

A. `1075.2Lt`
B. `739.2 L t`
C. `44.8 L t`
D. `67.2 L t`

Answer

B

Explanation

KI is limiting reagent `:. " "3 ` mole of KI will give 33 mole of `NO_(2)` according to stoichlometry.