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14 moles of A and 20 moles of B, 8 moles...

14 moles of A and 20 moles of B, 8 moles of C is formed in the following reaction `3A+4Brarr2C` then.

A

8 mole of B react

B

10 mole of A react

C

4 mole of B left

D

8 mole of A left.

Text Solution

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The correct Answer is:
3

`{:(,3A,+,4B,rarr,2C),(t=0" moles",14,,20,,0),(t=t_(eq),14-8xx(3)/(2),,20-8xx(4)/(2),,8):}`
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