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The melting point of a solid is 300K and...

The melting point of a solid is `300K` and its latent heat of fusion is `600 cal mol^(-1)`. The entropy change for the fusion of 1 mole of the solid ( in cal `K^(-1))` at the same tempertre would be `:`

A

200

B

2

C

`0.2`

D

20

Text Solution

Verified by Experts

The correct Answer is:
2
`DeltaS=(DeltaH_(f))/(T_(f))=(600)/(300)=2`
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