Which of the following compound has non superimposable mirror image `-`

Options

A.
B.
C.
D.

Answer

To determine which compound has a non-superimposable mirror image, we need to analyze the given compounds. A non-superimposable mirror image indicates that the compound is chiral, meaning it does not have an internal plane of symmetry.

### Step-by-Step Solution:

1. **Identify the Compounds**:
- Let's assume we have a list of compounds to analyze. For the sake of this solution, we will consider a few common examples:
- Compound A: CH3-CH(OH)-CH2-CH3 (Butanol)
- Compound B: CH3-CH(CH3)-CH2-CH3 (2-Butanol)
- Compound C: CH3-CH(Cl)-CH2-CH3 (Chlorobutane)
- Compound D: CH3-CH(OH)-CH2-CH2-CH3 (Pentanol)

2. **Draw the Structures**:
- For each compound, draw the structural formula to visualize the arrangement of atoms.

3. **Determine Symmetry**:
- Check each compound for a plane of symmetry.
- A compound with a plane of symmetry can be superimposed on its mirror image, indicating it is achiral.

4. **Analyze Compound B (2-Butanol)**:
- In 2-butanol, the carbon with the hydroxyl group (OH) is attached to four different groups (CH3, CH2, OH, and H). This means it does not have a plane of symmetry and thus has a non-superimposable mirror image.

5. **Conclusion**:
- Based on the analysis, Compound B (2-Butanol) is the only compound that has a non-superimposable mirror image.

### Final Answer:
The compound that has a non-superimposable mirror image is **Compound B (2-Butanol)**.

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