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There is a conductor with cavity of rad...

There is a conductor with cavity of radius `R` as shown in figure. A point charge `Q` is placed at `R//2` distance from centre of cavity.
A point `P` is at `r` distance from centre of conductor. Then,

A

charge density at iner surface of cavity will be non uniform

B

charge density at surface of conductor will be uniform

C

electric field at point `P` is `Q/(4pi epsilon_(0)r^(2))`

D

force on charge `Q` is non zero

Text Solution

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The correct Answer is:
A, B, C, D

Electric field lines kill of on surface on conductor.
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