In the system shown in the figure , a bead of mass `m` can slide on the string. There is friction beween the bead and the string. Block `B` has mass equal to twice that of the bead. The system is released from rest with lenth `l=18.75m` of the string hanging below the bead. Assuming the pulley and string to be massless. Find the distance (in meter) moved by the block `B` before the bead slips out of the thread.

Answer

`0006.25`

Explanation

`mg-T=ma_(1)`
`2mg-2G=2ma_(2)`
So, `a_(1)=a_(2)`
Relative acceleration of bead with respect to end `=3a`
`:.` displacement of block `x=1/2"at"^(2)=l/3=6.25m`