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A thin non-conducting hemispherical shel...

A thin non-conducting hemispherical shell contains a positive charge `q` on it, which uniformly distributed on the shell. A point `P` lies on the diameter of shell as show in figure. Then the direction of electric field at the point `'P'` is

A

B

C

D

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The correct Answer is:
C
`E_(1)` and `E_(2)` are the magnitude of electric field due to upper hemispherical shell and lower spherical shell respectively, whose components along the diameter and its perpendicular direction are shown in the figure. By the combination of two hemispherical shells: At `P, E_(11)=E_(21)` and `E_(0)=E_(20)=0`
net electric field must be zero.
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