Three capacitor `C_(1)=6F, C_(2)=3F` and `C_(3)=4F` are separately charged with battery such that charge on each capacitor are `36C, 24C` and `40C` respectively and then disconnected with the battery. After that they are connected in a circuit along with an uncharged capacitor `C_(4)=4F` and a battery of emf `=4` volts as shown figure. Now the switch `S` is closed. Choose is correct option (s).

Options

A. Final charge on capacitor `C_(4)=4C`
B. Final charge on capacitor `C_(2)=24C`
C. Final charge on capacitor `C_(3)=36C`
D. Amount of charge flow in circuit `=` zero

Answer

B, D

Explanation

By applying Kirchhoff's law
`-4+q/4+(-40+q)/4+(24+q)/3+(36+q)/6=0`
`-4+q/4-10+q/4+8+q/3+6+q/6=0`
`q/4+1/4+1/3+1/6=0`
`impliesq=0`
Hence, there is no flow of charge.