A circuit shown in the figure contains a box having either a capacitor or an inductor. The power factor of the circuit is 0.8, while current lags behind the voltage. Then find the inductance/capacitance of the box is S.I. unit (take `pi=3.2`). The circuit draws 1 ampere current.

Answer

`00002.50`

Explanation

`X_(C)=(V_(C))/I=1000/1=1000Omega`
Current lags behind voltage
So, box has an inductor
Power factor `=0.8=R 800/(sqrt((800)^(2)+(X_(L)-1000)^(2)))`
`X_(L)=1600Omega`
`=omegaL=1600`
`L=1600/(2xx3.2xx100)=2.5H`