A conductor of mass `m=5kg` and length `l=4m` is placed on horizontal surface and a uniform magnetic field `B=2` Tesla exist parallel to horizontal surface but perpendicular to the conductor. Suddenly, a certain amount of charge is passed through it, then it is found to jump to a height `h=5m`. Then, find the amount of charge that passes through the conductor in coulomb. (take `g=10m//s^(2)`)

Answer

`00006.25`

Explanation

Impulse, `FDeltat=m sqrt(2gh)`
`(ilB)Deltat=msqrt(2gh)`………(i)
`iDeltat=Deltaq`
`Deltaq=(msqrt(2gh))/(Bl)=(5sqrt(2xx10xx5))/(2xx4)=6.25` Coulomb