If the dimension of a physical quantity `(EB)/(mu)` is `M^(a)L^(b)T^(c)`. Find the value of `((b-c)/a)`. Here
`Eimplies` magnitude of electric field
`Bimplies` Magnitude of magnetic field
`muimplies` Permeability of medium

Answer

3

Explanation

`(EB)/(mu)=(B^(2)C)/(mu)=` Energy density `xx` speed
`=` Energy per unit volume `xx` speed
`= ("Energy")/("volume")xx"speed"`
`(ML^(2)T^(-2))/(L^(3))xxLT^(-1)=ML^(0)T^(-3)`
Here `a=1, b=0 c=-3implies(b-c)/a=(0-(-3))/1=3`