`{:(,"Column I",,"Column 2",,"Column 3",),(,"Enthalpy and",,"Entropy change",,"Entropy change of",),(,"internal energy change",,"of the system",,"the surroundings",),((I),DeltaH=0,(i),(DeltaH)/(T),(P),-(DeltaH)/(T),),((II),DeltaU=0,(ii),0,(Q),0,),((III),DeltaH=+ve,(iii),+ve,(R),+ve,),((IV),DeltaH=-ve,(iv),-ve,(S),-ve,):}`

Options

A. `(III)-(ii)-(R )`
B. `(I)-(iii)-(Q)`
C. `(I)-(i)-(R )`
D. `(II)-(i)-(R )`

Answer

B

Explanation

`{:(,DeltaH=-ve,),(P_(4)("red")rarrP_(4)("black"),DeltaS=-ve,),(,DeltaS_("surr")=+ve,):}`
For an irreversible adibatic compression,
`DeltaH=+ve`
`DeltaS=+ve`
`DeltaS_("surr")=0`
For interconversion of enantiomers,
`DeltaH=0`
`DeltaS=+ve`
`DeltaS_("surr")=0`