A thin rod of mass m has an angular velocity `omega_(0)` while rotating on a smooth surface. Determine its new angular velocity (in rads//s) just after its end strike and hooks onto the peg and the rod starts to rotate about P without rebounding. Solve the problem using the parameters given. `m=2kg, omega_(0)= rad//s, l=1.5 m`

Answer

1

Explanation

(a) From conservation of angular momentum about P
`[(1)/(12)ml^(2)]omega_(0)=[(1)/(3)ml_(2)]omega`
`omega= (1)/(4)omega_(0)`
(b) From part (a) `omega=(1)/(4)omega_(0)=(1)/(4)(4)=1rad//s`