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Let P(1): x+y+z=0 P(2)x+2y+3y=0 P(3...

Let `P_(1): x+y+z=0`
`P_(2)x+2y+3y=0`
`P_(3): x+3y+5z=0` be three planes
`L_(1)` is the line of intersection of `P_(1) & P_(2)`
Let `P(2,1-1)` be point on `P_(3)` If `(alpha,beta,lambda)` is image of point P in line `L_(1)` then value of `|alpha + beta+ lambda|` is

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Verified by Experts

The correct Answer is:
2

Direction ratio of line `L_(1)` is `|(hat(i),hat(j),hat(k)),(1,1,1),(1,2,3)|`
therefore Line `L_(1):(x)/(1)=(y)/(-2)=(z)/(1)`

`(lambda-2)-2(-2lambda-1)+(lambda+1)1=0`
`6lambda=-1implies lambda=(-1)/(6)`
`(alpha+2)/(2)=lambda,(beta+1)/(2)=-2lambda,(lambda-1)/(2)=lambda`
`implies alpha+beta+lambda=-2-1+1+2lambda-41+2lambda=-2`
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