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Frequency of a wave is 6 xx 10^(15) Hz. ...

Frequency of a wave is `6 xx 10^(15)` Hz. The wave is

A

radiowave

B

microwave

C

x-ray

D

Ultravoilet

Text Solution

AI Generated Solution

The correct Answer is:
To determine the type of electromagnetic wave corresponding to a frequency of \(6 \times 10^{15}\) Hz, we can refer to the frequency ranges of different types of electromagnetic waves. ### Step-by-Step Solution: 1. **Identify the Frequency Range**: We need to categorize the given frequency \(6 \times 10^{15}\) Hz into the appropriate range of electromagnetic waves. The common categories of electromagnetic waves, in order of increasing frequency, are: - Radio Waves: \(10^4\) Hz to \(10^8\) Hz - Microwaves: \(10^8\) Hz to \(10^{12}\) Hz - Infrared: \(10^{12}\) Hz to \(4 \times 10^{14}\) Hz - Visible Light: \(4 \times 10^{14}\) Hz to \(7.5 \times 10^{14}\) Hz - Ultraviolet: \(7.5 \times 10^{14}\) Hz to \(10^{16}\) Hz - X-rays: \(10^{16}\) Hz to \(10^{19}\) Hz - Gamma Rays: Above \(10^{19}\) Hz 2. **Locate the Given Frequency**: The frequency \(6 \times 10^{15}\) Hz falls between \(7.5 \times 10^{14}\) Hz (the upper limit of visible light) and \(10^{16}\) Hz (the lower limit of ultraviolet light). 3. **Determine the Type of Wave**: Since \(6 \times 10^{15}\) Hz is greater than \(7.5 \times 10^{14}\) Hz but less than \(10^{16}\) Hz, we can classify this frequency as belonging to the **Ultraviolet (UV)** range of electromagnetic waves. 4. **Conclusion**: Therefore, the wave with a frequency of \(6 \times 10^{15}\) Hz is classified as an **Ultraviolet wave**. ### Final Answer: The wave is an **Ultraviolet wave**.
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