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A stone with weight W is thrown vertical...

A stone with weight W is thrown vertically upward into air with initial speed u. Due to air friction a constant force R acts on the stone, throughout its flight. Find – (a) the maximum height reached and (b) speed of stone on reaching the ground.

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The correct Answer is:
(a) `(Wu^(2))/(2g(W+R))`
(b) v=u((W-R)/(W+R))^(1//2)`
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