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A block of mass M is placed on a horizon...

A block of mass M is placed on a horizontal surface having coefficient of friction m. A constant pulling force `F=(Mg)/2` is applied on the block to displace it horizontally through a distance d. Find the maximum possible kinetic energy acquired by the block.

Text Solution

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The correct Answer is:
`Mgd[(sqrt(u^(2)+1)/2-mu]`
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Knowledge Check

  • A block of mass m is lying on horizontal surface of coefficient of friction mu. A force is applied to the block at an angle theta with the horizontal. The block will move with a minimum force F if

    A
    `mu =tan theta`
    B
    `mu= cos theta`
    C
    `mu= sin theta`
    D
    `mu = cot theta`
  • A block of mass m is placed on a rough horizontal surface. The coefficent of friction between them is mu . An external horizontal force is applied to the block and its magnitude is gradually increased. The force exerted by the block on the surface is R.

    A
    The magnitude of R gradually increase.
    B
    `R le mg sqrt(mu^(2)+1)`.
    C
    The angle made by R with the vertical will gradually increase.
    D
    The angle made by R with the vertical `le tan^(-1)mu`.
  • A block of mass m=5kg is resting on a rough horizontal surface for which the coefficient of friction is 0.2 . When a force F=40N is applied, the acceleration of the block will be (g=10m//s^(2)) .

    A
    `5.73m//sec^(2)`
    B
    `8.0m//sec^(2)`
    C
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    D
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