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A ball is hanging vertically by a light ...

A ball is hanging vertically by a light inextensible string of length L from fixed point O. The ball of mass m is given a speed u at the lowest position such that it completes a vertical circle with centre at O as shown. Let AB be a diameter of circular path of ball making an angle `theta` with vertical as shown. (g is acceleration due to gravity)

a) Let `T_A` and `T_B` be tension in string when ball is at A and B respectively, then find `T_A` – `T_B`. (b) Let `vec(a)_(A)` and `vec(a)_(B)` be acceleration of ball when it is at A and B respectively, then find the value of `|vec(a)_(A)+vec(a)_(B)|`

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Verified by Experts

The correct Answer is:
`(a) 6mg cos theta `
`(b) gsqrt(4+12 cos^(2) theta)`
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