A semicircular wire frame of radius R is...

A semicircular wire frame of radius R is standing vertical on a horizontal table. It is pulled horizontally towards right with a constant acceleration. A bead of mass m remain in equilibrium (relative to the semicircular wire) at a position where radius makes an angle q with horizontal. There is no friction between the wire and the bead. The bead is displaced a little bit in upward direction and released. Calculate the speed of the bead relative to the wire at the instant it strikes the table. Assume that all throughout the semicircular wire keeps moving with constant acceleration.

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The correct Answer is:

`sqrt(2gR((1+cos theta_(0))/(sin theta_(0))))`

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