The angular speed of rotation of the earth is `omega=7.27xx10^(-5)rads^(-1)`and its radius is `R=6.37xx10^(6)m.` Calculate the acceleration of a man standing at a place at `40^(@)` latitude. `[cos40^(@)=10.77]` If the earth suddenly stops rotating, the acceleration due to gravity on its surface will become`g_(0)=9.82ms^(-2).` Find the effective value of acceleration due to gravity (g) at `40^(@)` latitude taking into account the rotation of the earth.

Answer

0.026`ms^(-2)`
9.80 `ms^(-2)`