A small steel ball of mass `m = 5g` is dropped from a height of `2.0 m` on a hard floor. `0.001%` of its kinetic energy before striking the floor gets converted into a sound pulse having a duration of `0.4 s`. Estimate how far away the sound can be heard if minimum audible intensity is `2.0 xx 10^( –8) Wm^( –2)` [Actually it is much less but to account for background sound we are assuming it to be high]. Assume no attenuation due to atmospheric absorption.

Answer

3.15 m