A 50 g ice at `0^(@)C` is added to 200 g water at `70^(@)C` taken in a flask. When the ice has melted completely, the temperature of the flask and the contents is reduced to `40^(@)C`. Now to bring down the temperature of the contents to `20^(@)C`, find a further amount of ice that is to be added.
Text Solution
Verified by Experts
The correct Answer is:
`50g`
Topper's Solved these Questions
CALORIMETRY
ARIHANT|Exercise Level 2|6 Videos
CALORIMETRY
ARIHANT|Exercise Level 3|1 Videos
BASIC MATHS
ARIHANT|Exercise Basic Maths|23 Videos
ELASTICITY
ARIHANT|Exercise Level 3|1 Videos
Similar Questions
Explore conceptually related problems
10 g ice at 0^(@)C is mixed with 20 g of water at 20^(@)C . What is the temperature of mixture?
If 2g ice at 0^(0)C is dropped into 10g water at 80^(0)C then temperature of mixture is
One gram of ice at 0^(@)C is added to 5 gram of water at 10^(@)C . If the latent heat of ice be 80 cal/g, then the final temperature of the mixture is -
Ice at 0^@C is added to 200 g of water initially at 70^@C in a vacuum flask. When 50 g of ice has been added and has all melted the temperature of the flask and contents is 40^@C . When a further 80 g of ice has been added and has all melted the temperature of the whole becomes 10^@C . Find the latent heat of fusion of ice.
540 g of ice at 0^(@)C is mixed with 540 g of water at 80^(@)C . The final temperature of the mixture is
30 g ice at 0”^(@)C is mixed with 25 g steam at 100”^(@)C . Find the final temperature and composition