An ideal gas is taken through a thermodynamic cycle ABCDA. In state A pressure and volume are `P_(0)` and `V_(0)` respectively. During the process `A rarr B`, work done by the gas is zero and its temperature increases two fold. During the process `B rarr C`, internal energy of the gas remains constant but work done by it is `W_(BC) = – P_(0)V_(0) ln2`. In the process `C rarr D`, the temperature decreases by 50% while the volume does not change. In the process `D rarr A` the temperature of the gas does not change.
(a) Draw pressure – volume (P–V) and pressure – density `(P – rho)` graph for the cyclic process.
(b) Calculate work done on the gas during the cycle.

Answer

(a) `(##IJA_PHY_V02_C04_E01_041_A01##)`
(b) `W = (1)/(2)P_(0)V_(0) ln_(2)`