`10gm` of a solute is dissolved in `80gm` of acctone V.P. of this sol`=271mm "of" Hg`. If V.P. of acctone is `283mm "of" Hg`. Calculate molar mass of solute.

Explanation

`(P^(0)-P)/(P_(s))=(w)/(m)xx(M)/(W)`
`rArr (283-271)/(271)=(10)/(m)xx(58)/(80)`
`m=163 gm//mol`.