If `0.1M` solutions of `K_(4)[Fe(CN)_(6)]` is prepared at `300K` then its density`=1.2gm//mL`. If solute is `50%` dissociated calculate `DeltaP` of solutions if `P` of pure water `=25mm "of" Hg`. `(K=39,Fe=56)`

Explanation

`(P^(0)-P_(s))/(P_(s))=i(w)/(m)xx(M)/(W)`
`(P^(0)-P_(s))/(P_(s))=(imxxM)/(1000)`
`=((3xx0.1xx1000)/(1000xx1.2-1.2xx368))xx(18)/(1000)`
`(P^(0))/(P_(s))=1+7.12xx10^(-3)`
`P_(0)=24.82mm "of" Hg`
`Deltap=25-24.82=0.18 mm "of" Hg`