`1 Lit`. Of aq. Solution of urea having density`=1.060gm//mL` is found to have `DeltaT_(b)=0.5^(@)C`, if temp. of this solution increase to `101.5^(@)C` then calculate amount of water which must have gone is vapour state upto this pt. given `K_(b)=0.5K kg mol^(-1)` for water

Explanation

To solve the problem, we will follow these steps:

### Step 1: Calculate the mass of the solution
Given the density of the solution is 1.060 g/mL and the volume is 1 L (1000 mL), we can calculate the mass of the solution.

\[ \text{Mass of solution} = \text{Density} \times \text{Volume} = 1.060 \, \text{g/mL} \times 1000 \, \text{mL} = 1060 \, \text{g} \]
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