If urea (aq) solution at `500K` has `O.P.=2.05` atm. `&` glucose solution at `300K` has `OP=1.23` atm. If `200mL` of `I^(st)` solution `& 400 ml` of `2^(nd)` solution are mixed at `400K` then calculate `O.P.` of resulting solution at `400K` (assume molarity is not dependent on temp.)

Explanation

`C_("urea")=(2.05)/(Rxx500)=0.05 rArr V_("urea")=2CO mL`
`C_("glucose")=(1.23)/(Rxx300)=0.05 rArr V_("glucose")=400mL`
`C_("total")=(C_(1)V_(1)+C_(2)V_(2))/(V_(1)+V_(2))=(0.05xx200+0.05xx400)/(600)=0.05`
`pi=CRT=0.05xx0.082xx400`
`pi=1.64` atm