`Ba^(2+)` ions, `CN^(-) & Co^(2+)` ions form a water soluble complex with `Ba^(2+)` ions as free cations for a `0.01M` solution of this complex, osmotic pressure `=0.984` atm `&` degree of dissociation `=75%`. Then find ccordination number of `Co^(2+)` ion in this complex (`T=300K, R=0.082L "mol"^(-1) K^(-1)`)

Explanation

To solve the problem, we need to determine the coordination number of the `Co^(2+)` ion in the complex formed with `Ba^(2+)` ions and `CN^(-)` ions. We are given the osmotic pressure, the degree of dissociation, and the molarity of the solution. Let's break it down step by step.

### Step 1: Use the osmotic pressure formula
The osmotic pressure (\( \Pi \)) is given by the formula:
\[ \Pi = iCRT \]
Where:
...