Calculate the molality of `K_(2)CO_(3)` solution which is formed by dissolving `2.5g` of it in one litre of solution. Density of solution is `0.85g ml^(-1)`. (At. wt. of `K=39,C=12,O=16)`

Explanation

To calculate the molality of a \( K_2CO_3 \) solution formed by dissolving 2.5 g of it in one liter of solution, we will follow these steps:

### Step 1: Calculate the Molecular Weight of \( K_2CO_3 \)

The molecular weight (molar mass) of \( K_2CO_3 \) can be calculated using the atomic weights of its constituent elements:

- Potassium (K): \( 39 \, \text{g/mol} \) (2 atoms)
- Carbon (C): \( 12 \, \text{g/mol} \) (1 atom)
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