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Boiling point of a mixture of water and ...

Boiling point of a mixture of water and nitrobenzene is `99^(@)C`, the vapour pressure of water is `733 mm` of `Hg` and the atmospheric pressure is `760 n n` if `Hg`. The molecular weight of nitrobenzene is `123`. Find the ratio weights of the components of the distillate.

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The correct Answer is:
`3.973`

`(n_(W))/(n_(N))=(W_(w))/(18).(123)/(W_(N))=(733)/(33)rArr(W_(w))/(W_(N))=(18xx733)/(27xx123)=3.973`
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